65 lines
		
	
	
		
			2.3 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
		
		
			
		
	
	
			65 lines
		
	
	
		
			2.3 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
|   | /*
 | ||
|  |  * Copyright (c) 2003, 2007-14 Matteo Frigo | ||
|  |  * Copyright (c) 2003, 2007-14 Massachusetts Institute of Technology | ||
|  |  * | ||
|  |  * This program is free software; you can redistribute it and/or modify | ||
|  |  * it under the terms of the GNU General Public License as published by | ||
|  |  * the Free Software Foundation; either version 2 of the License, or | ||
|  |  * (at your option) any later version. | ||
|  |  * | ||
|  |  * This program is distributed in the hope that it will be useful, | ||
|  |  * but WITHOUT ANY WARRANTY; without even the implied warranty of | ||
|  |  * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the | ||
|  |  * GNU General Public License for more details. | ||
|  |  * | ||
|  |  * You should have received a copy of the GNU General Public License | ||
|  |  * along with this program; if not, write to the Free Software | ||
|  |  * Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA  02110-1301  USA | ||
|  |  * | ||
|  |  */ | ||
|  | 
 | ||
|  | 
 | ||
|  | #include "rdft/rdft.h"
 | ||
|  | 
 | ||
|  | /* Check if the vecsz/sz strides are consistent with the problem
 | ||
|  |    being in-place for vecsz.dim[vdim], or for all dimensions | ||
|  |    if vdim == RNK_MINFTY.  We can't just use tensor_inplace_strides | ||
|  |    because rdft transforms have the unfortunate property of | ||
|  |    differing input and output sizes.   This routine is not | ||
|  |    exhaustive; we only return 1 for the most common case.  */ | ||
|  | int X(rdft2_inplace_strides)(const problem_rdft2 *p, int vdim) | ||
|  | { | ||
|  |      INT N, Nc; | ||
|  |      INT rs, cs; | ||
|  |      int i; | ||
|  |       | ||
|  |      for (i = 0; i + 1 < p->sz->rnk; ++i) | ||
|  | 	  if (p->sz->dims[i].is != p->sz->dims[i].os) | ||
|  | 	       return 0; | ||
|  | 
 | ||
|  |      if (!FINITE_RNK(p->vecsz->rnk) || p->vecsz->rnk == 0) | ||
|  | 	  return 1; | ||
|  |      if (!FINITE_RNK(vdim)) { /* check all vector dimensions */ | ||
|  | 	  for (vdim = 0; vdim < p->vecsz->rnk; ++vdim) | ||
|  | 	       if (!X(rdft2_inplace_strides)(p, vdim)) | ||
|  | 		    return 0; | ||
|  | 	  return 1; | ||
|  |      } | ||
|  | 
 | ||
|  |      A(vdim < p->vecsz->rnk); | ||
|  |      if (p->sz->rnk == 0) | ||
|  | 	  return(p->vecsz->dims[vdim].is == p->vecsz->dims[vdim].os); | ||
|  | 
 | ||
|  |      N = X(tensor_sz)(p->sz); | ||
|  |      Nc = (N / p->sz->dims[p->sz->rnk-1].n) * | ||
|  | 	  (p->sz->dims[p->sz->rnk-1].n/2 + 1); | ||
|  |      X(rdft2_strides)(p->kind, p->sz->dims + p->sz->rnk - 1, &rs, &cs); | ||
|  | 
 | ||
|  |      /* the factor of 2 comes from the fact that RS is the stride
 | ||
|  | 	of p->r0 and p->r1, which is twice as large as the strides | ||
|  | 	in the r2r case */ | ||
|  |      return(p->vecsz->dims[vdim].is == p->vecsz->dims[vdim].os | ||
|  | 	    && (X(iabs)(2 * p->vecsz->dims[vdim].os) | ||
|  | 		>= X(imax)(2 * Nc * X(iabs)(cs), N * X(iabs)(rs)))); | ||
|  | } |